Arrange the following solutions according to decreasing order of osmotic pressure under similar condition of temperature and assuming complete dissociation A. 0.2 ~m~ KCl B. 0.3 ~m~ MgSO ₄ C. 0 1 ~m~ BaCl ₂ D. 0.5 ~m~ Al ₂ ( SO ₄ )₃

Step-by-step solution

Osmotic pressure = iCRT , where R and T are constant. Therefore, the osmotic pressure is proportional to the product iC . Assuming complete dissociation, we calculate this product for each solution. For 0.2 m KCl , i = 2 and C = 0.2 , so iC = 2 0.2 = 0.4 . For 0.3 m MgSO ₄ , i = 2 and C = 0.3 , so iC = 2 0.3 = 0.6 . For 0.1 m BaCl ₂ , i = 3 and C = 0.1 , so iC = 3 0.1 = 0.3 . For 0.5 m Al ₂( SO ₄)₃ , i = 5 and C = 0.5 , so iC = 5 0.5 = 2.5 . The iC values are 2.5 , 0.6 , 0.4 , and 0.3 . The decreasing order is ther