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Calculate the osmotic pressure of 0.03 mole of non electrolyte solute dissolved in 0.1 dm ^3 of water at 300 ~K [ R =0.0821 dm ^3 ~atm ~mol ⁻¹ ~K ⁻¹ ]

Options

  1. A7.4 atm
  2. B6 4 ~atm
  3. C8.0 atm
  4. D5.6 atm

Correct answer

A. 7.4 atm

Step-by-step solution

The osmotic pressure is given by the van't Hoff equation: = iCRT . For a non-electrolyte, the van't Hoff factor is i = 1 since there is no dissociation. The molar concentration is calculated from C = n/V = 0.03 mol / 0.1 dm ^3 = 0.3 mol/dm ^3 . Substituting the known values, = (1)(0.3 mol/dm ^3)(0.0821 dm ^3 atm mol ⁻¹ K ⁻¹)(300 K ) = 7.389 atm . Rounded to one decimal place, = 7.4 atm , which corresponds to option A .

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