MHT CET202415 May 2024Evening ShiftChemistrySolutionsActual
Calculate molar mass of a solute at 300 K if 400 mg of it is dissolved in 300 mL of water exerts osmotic pressure of 0.2 atm . ( R =0.0821 ~L ~atm ~K ⁻¹ ~mol ⁻¹ )
Options
- A90 ~g ~mol ⁻¹
- B120 ~g ~mol ⁻¹
- C164 ~g ~mol ⁻¹
- D180 ~g ~mol ⁻¹
Correct answer
C. 164 ~g ~mol ⁻¹
Step-by-step solution
aligned M ₂ & = W ₂ RT V & = 0.4 ~g 0.0821 dm ^3 atmK ⁻¹ ~mol ⁻¹ 300 ~K 0.2 ~atm 0.3 dm ^3 & =164.2 ~g ~mol ⁻¹ 164 ~g ~mol ⁻¹ aligned