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MHT CET202415 May 2024Morning ShiftChemistrySolutionsActual

What is the expected value of T_f for 1.25 ~m CaCl ₂ solution if 1.25 m sucrose solution has T _ f value x K ?

Options

  1. Ax K
  2. Bx 2 ~K
  3. C2 x K
  4. D3 x K

Correct answer

D. 3 x K

Step-by-step solution

For sucrose solution, ( T_f )₁=K_f m₁ . (i) For CaCl ₂ solution, ( T _ f )₂= iK _ f m ₂ (ii), From equation (i) and (ii), aligned ( T_f )₁ ( T_f )₂ & = m₁ i₂ ( T_f )₂ & = ( T_f )₁ i m₂ m₁ & = x K 3 1.25 ~m 1.25 ~m ( i for CaCl ₂=3 ) & =3 x K aligned

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