MHT CET20249 May 2024Evening ShiftChemistrySolutionsActual
Calculate the molar mass of solute in a solution prepared by dissolving 1 gram in 0.3 dm ^3 solvent having osmotic pressure 0.2 atm at 300 K. [ R =0.082 dm ^3 ~atm ~K ~mol ⁻¹ ]
Options
- A442 ~g ~mol ⁻¹
- B372 ~g ~mol ⁻¹
- C390 ~g ~mol ⁻¹
- D410 ~g ~mol ⁻¹
Correct answer
D. 410 ~g ~mol ⁻¹
Step-by-step solution
aligned M ₂ & = W ₂ RT V & = 1 ~g 0.0821 dm ^3 atmK ⁻¹ ~mol ⁻¹ 300 ~K 0.2 ~atm 0.3 dm ^3 & =410 ~g ~mol ⁻¹ aligned