MHT CET202312 May 2023Morning ShiftChemistrySolutionsActual
Calculate osmotic pressure of solution of 0.025 mole glucose in 100 ~mL water at 300 ~K . [ R =0.082 ~atm dm ^3 ~mol ⁻¹ ~K ⁻¹ ]
Options
- A1.54 ~atm
- B2.05 ~atm
- C6.15 ~atm
- D3.08 ~atm
Correct answer
C. 6.15 ~atm
Step-by-step solution
aligned & = MRT = n ₂ RT V & = 0.025 ~mol 0.082 dm ^3 ~atm ~mol ⁻¹ ~K ⁻¹ 300 ~K 0.1 dm ^3 & =6.15 ~atm aligned