If K_b denote molal elevation constant of water, then boiling point of an aqueous solution containing 36 ~g glucose ( molar mass =180) per dm ^3 is:

Step-by-step solution

The aqueous solution contains 36 ~g glucose per dm ^3 , so mass of solute W ₂ is 36 ~g . Assuming that the density of solution is 1 ~g / dm ^3 , the mass of solvent (water) is 1000 ~g . aligned & T _ b = 1000 ~K _ b W ₂ M ₂ ~W ₁ T _ b & = 1000 ~g ~kg ⁻¹ K _ b 36 ~g 180 ~g 1000 ~g T _ b & = 2 ~K _ b 10 T _ b & = T _ b - T _ b ^0 & ~T _ b = T _ b ^0+ T _ b & T _ b = (100+ 2 ~K _ b 10 )^ C aligned