MHT CET20228 Aug 2022Evening ShiftChemistrySolutionsActual
What is the molar mass of solute if a solution is prepared by dissolving 4.5 gram solute in 3 dm ^3 water having osmotic pressure 0.25 ~atm at 300 ~K ? ( R =0.0821 dm ^3 ~atm ~K ~K ⁻¹ ~mol ⁻¹ )
Options
- A148 ~g ~mol ⁻¹
- B160 ~g ~mol ⁻¹
- C172 ~g ~mol ⁻¹
- D136 ~g ~mol ⁻¹
Correct answer
A. 148 ~g ~mol ⁻¹
Step-by-step solution
= CRT 0.25= 4.5 M _ B 1000 3000 0.0821 300 M _ B =147.78 ~g / mol