Calculate osmotic pressure exerted by a solution containing 0.822 ~g of solute in 300 ~mL of water at 300 ~K . (Molar mass of solute =340 ~mol ⁻¹, R =0.0821 ~L ~atm ~mol ⁻¹ ~K ⁻¹ )

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Correct answer: B. 0.2 atm

aligned & = CRT & C = moles of solute volumeof solution ( ml ) 1000 & = 0.822 / 340 300 1000 & =0.008 & =0.008 0.0821 300 & =0.2 ~atm aligned

Calculate osmotic pressure exerted by a solution containing 0.822 ~g of solute in 300 ~mL of water at 300 ~K . (Molar mass of solute =340 ~mol ⁻¹, R =0.0821 ~L ~atm ~mol ⁻¹ ~K ⁻¹ )

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