What is vapour pressure of solution containing 0.1 mole solute dissolved in 1.8 10⁻² ~kg H ₂ O ? ( P ₁^0=24 ~mm Hg )

Step-by-step solution

aligned & P ^ - P _ s P ^ = X _ solute = n _ solute n _ solute + n _ solvent & Mass of water =1.8 10⁻² ~kg & =1.8 10⁻² 1000 ~g =18 ~g & Moles of water (solvent) = 18 18 =1 & 24- P _ s 24 = 0.1 0.1+1 = 0.1 1.1 & 24- P _ s 24 = 1 11 & P _ s =24- 24 11 =21.8 ~mm Hg . aligned