MHT CET202121 Sep 2021Morning ShiftChemistrySolutionsActual
What is boiling point of a decimolal aqueous solution of glucose if molal elevation constant for water is 0.52^ C kg mol ⁻¹ ?
Options
- A101.52^ C
- B99.95^ C
- C99.48^ C
- D100.052^ C
Correct answer
D. 100.052^ C
Step-by-step solution
aligned & T _ b = k _ b m & T _ b =0.52 0.1, ~m =0.1 (decimolal solution) & =0.052^ C & T _ b = T _ b - T _ b ^ ( T _ b ^ = . Boiling point of pure water) & 0.052^ C = T _ b -100^ C & T _ b =100.052^ C aligned