A solution of 6 ~g of solute in 100 ~g of water boils at 100.52^ C . The molal elevation constant of water is 0.52 ~K ~kg ~mol ⁻¹ . What is molar mass of solute?

Step-by-step solution

aligned & W ₂=6 ~g , ~W ₁=100 ~g , ~K _ b =0.52 Kg mol ⁻¹, ~T _ b 100.52^ C & T _ b = T _ b - T _ b ^ =(100.52+273)-(100+273) & =0.52 k aligned Now, M ₂= 1000 K _ b W ₂ T _ b W ₁ = 1000 ~g ~kg ⁻¹ 0.52 ~K ~kg ~mol ⁻¹ 6 ~g 0.52 ~K 100 ~g M ₂=60 ~g ~mol ⁻¹