60 ~g CH ₃ COOH dissolved in 1 dm ³ solvent, what is molality of solution ? (density =1 25 ~g / cm ³ )

Step-by-step solution

0.8 ~m Given, Volume =1 dm ³=10³ ~cm ³ Density =1.25 ~g / cm ³ Mass =60 ~g We know that, molahty (M)= Moles Mass of solvents Moles = Given mass Molar mass = 60 ~g 60 ~g / mol =1 ~mol Molality ( m )= Moles Volume Density m = 1 1000 ~cm ³ 1.25 ~g / cm ³ = 1 1.25 ~g 10³ 1 1.25 ~kg =0.8 ~m