A solution has an osmotic pressure of 'x' kPa at 300 ~K having 1 mole of solute in 10 5 ~m ³ of solution. If it's osmotic pressure is reduced to ( 1 10 )^ th of it's initial value, what is the new volume of solution?

Step-by-step solution

(A) array l = X kPa , V =10.5 ~m ³, ^ = X 10 kPa , V ^ =? = n v RT array i. X= 1 10.5 8.314 300 ; ii. X 10 = 1 V^ 8.314 300 By dividing equation (i) by (ii) aligned X X / 10 &= 1 10.5 8.314 300 1 1 / V^ 8.314 300 10 &= V^ 10.5 V^ =105 ~m ³ aligned