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MHT CET202013 Oct 2020Morning ShiftChemistrySolutionsActual

38 4 ~g of unknown substance (molar mass 384 ~g ~mol ⁻¹ ) and 116 ~g of acetone is used to prepare a solution at 313 ~K . If vapour pressure of pure acetone (molar mass 58 ~g ~mol ⁻¹ ) is 0.842 atmosphere, what is the vapour pressure of solution?

Options

  1. A0.650 ~atm
  2. B0.880 ~atm .
  3. C0.7999 ~atm .
  4. D0.958 ~atm

Correct answer

C. 0.7999 ~atm .

Step-by-step solution

n ₂= 38.4 384 =0.1 ~mol solute n ₁= 116 58 =2 ~mol solvent (acetone) Mole fraction ; x₁= n₁ n₁+n₂ = 2 2+0.1 =0.95 By Raoult's law, the vapour pressure of the solution is given by P=x₁ P₀=0.95 0.842 ~atm =0.7999 ~atm

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