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The molar concentration of chloride ions in the resulting solution of 300 ~mL of 3.0 M NaCl and 200 ~mL of 4.0 M BaCl ₂ will be

Options

  1. A1.7 M
  2. B1.8 M
  3. C5.0 M
  4. D3.5 M

Correct answer

C. 5.0 M

Step-by-step solution

4.0 M BaCl ₂ Ba ²⁺+ 2 4.0 M 2 Cl ⁻ Molar concentration of aligned Cl ⁻ &= M₁ V₁+M₂ V₂ V₁+V₂ &= 3.0 300+2 4.0 200 300+200 &= 900+1600 500 &=5.0 M aligned

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