Dissolution of 1.5 ~g of a non-volatile solute (mol. wt. =60 ) in 250 ~g of a solvent reduces its freezing point by 0.01 ^ C . Find the molal depression constant of the solvent.

Step-by-step solution

Depression in freezing point, array c T_ f =k_ f m where, m= molality = wt. of solute 1000 mol. wt. of solute array wt. of solvent aligned &= 1.5 1000 60 250 &=0.1 T_ f &=k_ f 0.1 0.01 &=k_ f 0.1 k_ f &= 0.01 0.1 &=0.1 ^ C molal ⁻¹ aligned