MHT CET202620 April 2026Evening ShiftChemistryStates of MatterActual
A mixture of 0.5 mol N ₂ gas, 1.0 mol O ₂ gas and 1.5 mol H ₂ gas exerts a total pressure of 18 bar. Find the partial pressure of O _ 2(g) .
Options
- A4.0 bar
- B6.0 bar
- C8.0 bar
- D10.0 bar
Correct answer
B. 6.0 bar
Step-by-step solution
Total number of moles in the mixture is: n_ total = n_ N₂ + n_ O₂ + n_ H₂ n_ total = 0.5 + 1.0 + 1.5 = 3.0 mol Mole fraction of O ₂ is: x_ O₂ = n_ O₂ n_ total = 1.0 3.0 = 1 3 According to Dalton's law of partial pressures, the partial pressure of O ₂ is: P_ O₂ = x_ O₂ P_ total P_ O₂ = 1 3 18 = 6.0 bar Answer: 6.0 bar