3.4 moles of an ideal gas occupies volume of 68 mL at 300 K . What would be the pressure of gas? ( R =8.314 ~J ~K ⁻¹ ~mol ⁻¹ )

Step-by-step solution

aligned & n =3.4 ~mol , ~T =300 ~K & ~V =68 ~mL =0.068 ~L , R =8.314 ~J ~K ⁻¹ ~mol ⁻¹ aligned According to ideal gas equation, PV = nRT aligned P = nRT ~V & = 3.4 ~mol 8.314 JK ⁻¹ ~mol ⁻¹ 300 ~K 0.068 dm ^3 & =124710 kPa aligned