What is the volume of a gas at 1.032 10^5 Nm ⁻² if it occupies 1 dm ^3 of volume at normal temperature and pressure?

Step-by-step solution

1 Nm ⁻²=1 ~Pa =0.9869 10⁻⁵ ~atm Normal pressure =1 ~atm aligned P ₁ ~V ₁= P ₂ ~V ₂ ~V ₁= 1 ~atm 1 dm ^3 (1.032 10^5 0.987 10⁻⁵ ) atm =0.982 dm ^3 aligned