How many moles of dioxygen are present in 8.314 10⁻³ ~m ^3 of it at 318 K having pressure 3.18 10^5 Nm ⁻² ? ( R =8.314 ~J ~K ⁻¹ ~mol ⁻¹ )

Step-by-step solution

aligned & n = PV RT = 3.18 10^5 ~N ~m ⁻² 8.314 10⁻³ ~m ^3 8.314 ~J ~K ⁻¹ ~mol ⁻¹ 318 ~K & = 26.438 10^2 ~N ~m 8.314 ~J ~mol ⁻¹ 318 ( 1 ~N ~m =1 Joule ) & n = 26.438 ~J 10^2 2643.85 ~J ~mol ⁻¹ =1 ~mole aligned