If two moles of an ideal gas at 546 ~K occupy a volume of 44.8 ~L . What is the pressure of ideal gas at 546 ~K ? ( R =0 0821 ~L ~atm ~mol ⁻¹ ~K ⁻¹ )

Step-by-step solution

n =2 ~mol , ~T =546 ~K , ~V =44.8 ~L , R =0.0821 ~L ~atm ~mol ⁻¹ ~K ⁻¹, P =? According to ideal gas equation, PV = n R T P= n R T V = 2 0.0821 546 44.8 =2.0 ~atm