Calculate the shortest wavelength in hydrogen spectrum emission of Lymen series ( R_H = 109677 , cm ⁻¹ )

Step-by-step solution

For the Lyman series, the transition is from n₂ to n₁ = 1 . The shortest wavelength corresponds to the maximum energy transition, which occurs when n₂ = . Using the Rydberg formula: 1 = R_H ( 1 n₁^2 - 1 n₂^2 ) Substituting n₁ = 1 and n₂ = : 1 = R_H ( 1 1^2 - 1 ^2 ) = R_H = 1 R_H Given R_H = 109677 cm ⁻¹ : = 1 109677 cm 9.117 10⁻⁶ cm Answer: 9.117 10⁻⁶ cm