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MHT CET202615 April 2026Evening ShiftChemistryStructure of AtomActual

If the velocity of the electron in Bohr's first orbit is 2.19 10^6 Ms ⁻¹ , Calculate the de Broglie wavelength associated with it. [h = 6.626 10⁻³⁴ J s & Mass of electrons = 9.10938 10⁻³¹ kg ]

Options

  1. A332 pm
  2. B313 pm
  3. C342 pm
  4. D323 pm

Correct answer

A. 332 pm

Step-by-step solution

The de Broglie wavelength is given by the relation: = h mv Substituting the given values: = 6.626 10⁻³⁴ 9.10938 10⁻³¹ 2.19 10^6 = 6.626 10⁻³⁴ 19.949 10⁻²⁵ = 0.3321 10⁻⁹ m = 332.1 10⁻¹² m 332 pm Answer: 332 pm

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