MHT CET202615 April 2026Morning ShiftChemistryStructure of AtomActual
Calculate the de Broglie wavelength of an electron in the first Bohr orbit of a hydrogen atom if the velocity of an electron in the first orbit is 2.2 10^6 ms ⁻¹ . [mass of electron = 9.1 10⁻³¹ kg, plank's constant (h) = 6.626 10⁻³⁴ J s]
Options
- A3.31 10⁻¹⁰ m
- B3.01 10⁻¹⁰ m
- C3.62 10⁻¹⁰ m
- D2.71 10⁻¹⁰ m
Correct answer
A. 3.31 10⁻¹⁰ m
Step-by-step solution
The de Broglie wavelength is given by the relation: = h mv Substituting the given values: = 6.626 10⁻³⁴ 9.1 10⁻³¹ 2.2 10^6 = 6.626 10⁻³⁴ 20.02 10⁻²⁵ = 0.331 10⁻⁹ m = 3.31 10⁻¹⁰ m Answer: 3.31 10⁻¹⁰ m