If the energy of an electron in the first Bohr orbit of the H-atom is -2.18 10⁻¹⁸ J then the energy of the electron in the second orbit will be

Step-by-step solution

The energy of an electron in the n -th Bohr orbit of a hydrogen atom is given by E_n = E₁ n^2 . Given E₁ = -2.18 10⁻¹⁸ J and n = 2 . Substituting the values, we get: E₂ = -2.18 10⁻¹⁸ 2^2 E₂ = -2.18 10⁻¹⁸ 4 E₂ = -0.545 10⁻¹⁸ J. Answer: -0.545 10⁻¹⁸ J