According to de-Broglie hypothesis if an electron of mass ' m ' is accelerated by potential difference ' V ' then associated wavelength is ' '. When a proton of mass ' M ' is accelerated through potential difference ' 9 ~V ' then the wavelength associated with it is

Step-by-step solution

Do Broglie relation = h P ...(1) Energy conservation, qV = K ...(2) Energy vs momentum relation K= p^2 2 m ...(3) Using equation (1), (2) and (3) aligned & = h p = h 2 Km & = h 2 qVm aligned Now, for proton of mass M that is accelerated through 9 ~V , the de-broglie wavelength can be written as, aligned & _ P = h 2 q (9 ~V ) M & _ p =3 M m & _ p = 3 m M aligned