MHT CET202618 April 2026Morning ShiftChemistrySurface ChemistryActual
Which from following anions has greater power for coagulation of positive sol?
Options
- ACl ^-
- B[ Fe(CN) ₆]⁴⁻
- CPO ₄²⁻
- DSO ₄²⁻
Correct answer
B. [ Fe(CN) ₆]⁴⁻
Step-by-step solution
According to the Hardy-Schulze rule, the coagulating power of an ion is directly proportional to the magnitude of its charge (valency). For the coagulation of a positive sol, an anion is required. The given anions and their charge magnitudes are: Cl ^- : 1 SO ₄²⁻ : 2 PO ₄³⁻ (given as PO ₄²⁻ in options) : 3 [ Fe(CN) ₆]⁴⁻ : 4 Since [ Fe(CN) ₆]⁴⁻ has the highest negative charge, it possesses the maximum coagulating power among the given options.