MHT CET202619 April 2026Morning ShiftMathematicsApplication of DerivativesActual
A tank with a rectangular base and rectangular sides, open at the top is made. Depth of the tank is 4 m and its volume is 36 cubic meters. For making a tank cost of base material used is Rs. 100 per sq. meter and that of sides is Rs. 50 per sq. meter. Then minimum cost of tank is ..............
Options
- ARs. 1100
- BRs. 2200
- CRs. 3300
- DRs. 4400
Correct answer
C. Rs. 3300
Step-by-step solution
Let the length and breadth of the base of the tank be x and y respectively. Given depth h = 4 m and volume V = 36 m ^3 . V = x y h 4xy = 36 xy = 9 Cost of the base = 100 xy = 100 9 = 900 Area of the four sides = 2(xh + yh) = 2(4)(x + y) = 8(x + y) Cost of the sides = 50 8(x + y) = 400(x + y) Total cost C = 900 + 400(x + y) To minimize C , we need to minimize x + y . Using AM-GM inequality for x, y > 0 : x + y 2 xy x + y 2 9 = 6 Minimum value of x + y is 6 , which occurs when x = y = 3 . Minimum cost C = 900 + 400(6