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MHT CET202618 April 2026Evening ShiftMathematicsApplication of DerivativesActual

If a particle moves such that the displacement (s) is proportional to the square of the velocity (v), then its acceleration (a) is

Options

  1. Aproportional to s^2
  2. Bproportional to 1/s
  3. Cproportional to 1/s^2
  4. Da constant

Correct answer

D. a constant

Step-by-step solution

Given s v^2 s = k v^2 where k is a constant. Differentiating both sides with respect to time t : ds dt = 2kv dv dt Since ds dt = v and dv dt = a : v = 2kv a a = 1 2k Since k is a constant, acceleration a is a constant. Answer: a constant

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