Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202615 April 2026Evening ShiftMathematicsApplication of DerivativesActual

The surface area of a spherical ball is increasing at the rate of 4 cm ^2 /second. The rate at which the radius is increasing when the surface area is 16 cm ^2 is

Options

  1. A0.5 cm/second
  2. B0.25 cm/second
  3. C0.125 cm/second
  4. D1 cm/second

Correct answer

B. 0.25 cm/second

Step-by-step solution

Let S be the surface area and r be the radius of the spherical ball. S = 4 r^2 Differentiating with respect to time t : dS dt = 8 r dr dt Given dS dt = 4 cm ^2 /s. When S = 16 cm ^2 : 4 r^2 = 16 r^2 = 4 r = 2 cm. Substituting the values into the derivative equation: 4 = 8 (2) dr dt 4 = 16 dr dt dr dt = 4 16 = 0.25 cm/s.

Practice Application of Derivatives on Quantrex Academy →

More from Application of Derivatives

Consider the quadratic equation a x^2+b x+c=0 , where 2 a+3 b+6 c=0 and let g(x)= a x^3 3 + b x^2 2 +c x . Statement-I : The given quadratic equation ax ^2+ bx + c =0 has at least 2025The difference between the absolute maximum and absolute minimum values of the function f(x)=2 x^3-15 x^2+36 x-30 on [-1,4] is 2025If f(x)=x e^ x(1-x) , x R , then f(x) is 2025The angle between the curves y ^2= x and x ^2= y at the point (1,1) is 2025If the tangent of the curve 4 y^3=3 a x^2+x^3 drawn at the point (a, a) forms a triangle of area 25 24 sq.units with the coordinate axes then a = 2025If the function f(x)= x- ^2 x is defined on the interval [- , ] , then f is strictly increasing in the interval 2025If the Lagrange's mean value theorem is applied to the function f(x)=e^x defined on the interval [1,2] and the value of c (1,2) is k , then e^ k-1 = 2025If the tangent to the curve x y+a x+b y=0 at (1,1) makes an angle Tan ⁻¹ 2 with X -axis, then ab a + b = 2025 Full Application of Derivatives list All MHT CET PYQs