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MHT CET202416 May 2024Evening ShiftMathematicsApplication of DerivativesActual

If x=-1 and x=2 are extreme points of f(x)= |x|+ x^2+x , then

Options

  1. A=-6, = 1 2
  2. B=-6, =- 1 2
  3. C=2, =- 1 2
  4. D=2, = 1 2

Correct answer

C. =2, =- 1 2

Step-by-step solution

According to the given condition, f ^ (-1)=0 and f ^ (2)=0 f (x)= |x|+ x^2+x array ll & f ^ (x)= x +2 x+1 & f ^ (-1)=0 +2 =1 ...(i) & and f ^ (2)=0 +8 =-2...(ii) array From (i) and (ii), we get =2 and = -1 2

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