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MHT CET202411 May 2024Evening ShiftMathematicsApplication of DerivativesActual

The maximum value of the function f (x)=2 x^3-15 x^2+36 x-48 on the set A = x |x^2+20 9 x is

Options

  1. A-16
  2. B-7
  3. C16
  4. D7

Correct answer

D. 7

Step-by-step solution

array ll & Let f (x)=2 x^3-15 x^2+36 x-48 & f ^ (x)=6 x^2-30 x+36=0 at x=3,2 & f ^ (x)=12 x-30 & ~A = x x^2-9 x+20 0 =[4,5] & 2,3 ~A & At x=4, f (x)=-16 and at x=5, f (x)=7 & Maximum value of f (x) is at x=5 & Maximum value of f (x) is 7 . array

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