MHT CET20249 May 2024Morning ShiftMathematicsApplication of DerivativesActual
Let C be a curve given by y(x)=1+ 4 x-3 , x 3 4 . If P is a point on C , such that the tangent at P has slope 2 3 , then a point through which the normal at P passes, is
Options
- A(1,7)
- B(3,-4)
- C(4,-3)
- D(2,3)
Correct answer
A. (1,7)
Step-by-step solution
aligned & y(x)=1+ 4 x-3 & ~d y ~d x = 4 2 4 x-3 = 2 4 x-3 & 2 4 x-3 = 2 3 & x=3 & y=4 aligned Equation of normal is aligned & y-4= -3 2 (x-3) & 2 y-8=-3 x+9 & 3 x+2 y-17=0 aligned Option (A) i.e., (1,7) satisfies above equation.