MHT CET20244 May 2024Evening ShiftMathematicsApplication of DerivativesActual

The approximate value of ⁻¹(0.999) is (use =3.1415 )

Options

A0.7843
B0.7849
C0.7847
D0.7851

Correct answer

B. 0.7849

Step-by-step solution

aligned & Let f (x)= ⁻¹ x & f ^ (x)= 1 1+x^2 aligned Here, a =1 and h =-0.001 aligned f(a+h) f(a) & +h f^ (a) ⁻¹(0.999) & 4 + 1 1+1 (-0.001) & 4 - 0.001 2 & 4 -0.0005 & 3.1415 4 -0.0005 & 0.7849 aligned

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