Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20244 May 2024Evening ShiftMathematicsApplication of DerivativesActual

If f (x)= ( ^4 x+ ^4 x ), 0 x 2 , then the function has minimum value _______ at x= ________.

Options

  1. A0.7934, 9
  2. B1 2 , 4
  3. C5 8 , 3
  4. D0.75, 8

Correct answer

B. 1 2 , 4

Step-by-step solution

aligned f(x) & = ^4 x+ ^4 x & = ( ^2 x+ ^2 x )^2-2 ^2 x ^2 x & =1- 1 2 ( 2 x)^2 aligned Since 0 ^2 2 x 1 0 - 1 2 ^2 2 x - 1 2 aligned & 1+0 1- 1 2 ^2 2 x 1- 1 2 & 1 ^4 x+ ^4 x 1 2 aligned aligned & 1- 1 2 ( 2 x)^2= 1 2 & ( 2 x)^2=1 & ( 2 x)^2= ( 2 )^2 & 2 x= 2 & x= 4 aligned

Practice Application of Derivatives on Quantrex Academy →

More from Application of Derivatives

Consider the quadratic equation a x^2+b x+c=0 , where 2 a+3 b+6 c=0 and let g(x)= a x^3 3 + b x^2 2 +c x . Statement-I : The given quadratic equation ax ^2+ bx + c =0 has at least 2025The difference between the absolute maximum and absolute minimum values of the function f(x)=2 x^3-15 x^2+36 x-30 on [-1,4] is 2025If f(x)=x e^ x(1-x) , x R , then f(x) is 2025The angle between the curves y ^2= x and x ^2= y at the point (1,1) is 2025If the tangent of the curve 4 y^3=3 a x^2+x^3 drawn at the point (a, a) forms a triangle of area 25 24 sq.units with the coordinate axes then a = 2025If the function f(x)= x- ^2 x is defined on the interval [- , ] , then f is strictly increasing in the interval 2025If the Lagrange's mean value theorem is applied to the function f(x)=e^x defined on the interval [1,2] and the value of c (1,2) is k , then e^ k-1 = 2025If the tangent to the curve x y+a x+b y=0 at (1,1) makes an angle Tan ⁻¹ 2 with X -axis, then ab a + b = 2025 Full Application of Derivatives list All MHT CET PYQs