Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202311 May 2023Morning ShiftMathematicsApplication of DerivativesActual

A curve passes through the point (1, 6 ) . Let the slope of the curve at each point (x, y) be y x + ( y x ), x>0 , then, the equation of the curve is

Options

  1. A( y x )= (x)+ 1 2
  2. Bcosec ( y x )= (x)+2
  3. C( 2 y x )= (x)+2
  4. D( 2 y x )= (x)+ 1 2

Correct answer

A. ( y x )= (x)+ 1 2

Step-by-step solution

aligned & d y ~d x = y x + ( y x ) & Put y= v x & d y ~d x = v +x dv d x & v +x dv d x = v + v & v dv = 1 x ~d x aligned Integrating both sides, we get aligned & V = (x)+ c & ( y x )= (x)+ c aligned The curve passes through (1, 6 ) . ( 6 )= (1)+c c= 1 2 Equation (ii) becomes ( y x )= (x)+ 1 2

Practice Application of Derivatives on Quantrex Academy →

More from Application of Derivatives

Consider the quadratic equation a x^2+b x+c=0 , where 2 a+3 b+6 c=0 and let g(x)= a x^3 3 + b x^2 2 +c x . Statement-I : The given quadratic equation ax ^2+ bx + c =0 has at least 2025The difference between the absolute maximum and absolute minimum values of the function f(x)=2 x^3-15 x^2+36 x-30 on [-1,4] is 2025If f(x)=x e^ x(1-x) , x R , then f(x) is 2025The angle between the curves y ^2= x and x ^2= y at the point (1,1) is 2025If the tangent of the curve 4 y^3=3 a x^2+x^3 drawn at the point (a, a) forms a triangle of area 25 24 sq.units with the coordinate axes then a = 2025If the function f(x)= x- ^2 x is defined on the interval [- , ] , then f is strictly increasing in the interval 2025If the Lagrange's mean value theorem is applied to the function f(x)=e^x defined on the interval [1,2] and the value of c (1,2) is k , then e^ k-1 = 2025If the tangent to the curve x y+a x+b y=0 at (1,1) makes an angle Tan ⁻¹ 2 with X -axis, then ab a + b = 2025 Full Application of Derivatives list All MHT CET PYQs