MHT CET20227 Aug 2022Morning ShiftMathematicsApplication of DerivativesActual
If y=4 x-5 is tangent to the curve y^2=p x^3+q at (2,3) , then
Options
- Ap=2, q=-7
- Bp=2, q=7
- Cp=-2, q=7
- Dp=-2, q=-7
Correct answer
A. p=2, q=-7
Step-by-step solution
aligned & (2,3) lies on y^2=p x^3+q & 3^2=P 2^3+q aligned from (i) and (ii) q=-7