MHT CET202124 Sep 2021Evening ShiftMathematicsApplication of DerivativesActual

The distance ' s ' in meters covered by a particle in t seconds is given by s=2+27 t-t^3 . The particle will stop after distance.

Options

A65 meters
B80 meters
C56 meters
D60 meters

Correct answer

C. 56 meters

Step-by-step solution

s =2+27 t - t ^3 and particle stops when its velocity is zero. ds dt =27-3 t ^2=0 t ^2=9 t =3 sec . Distance covered in 3 sec , is S _ ( t =3) =2+27(3)-(3)^3=56 ~m

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