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MHT CET202123 Sep 2021Evening ShiftMathematicsApplication of DerivativesActual

10 is divided into two parts such that the sum of double of the first and square of the other is minimum, then the numbers are respectively

Options

  1. A9,1
  2. B8,2
  3. C6,4
  4. D7,3

Correct answer

A. 9,1

Step-by-step solution

Let the two parts of 10 be x and (10-x) . f(x)=2(10-x)+x^2=x^2-2 x+20 f^ (x)=2 x-2 and when f^ (x)=0 , we get x=1 f ^ ( x )=2>0 f ( x ) is minimum at x =1 . Thus the parts are 1,9 .

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