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MHT CET202019 Oct 2020Evening ShiftMathematicsApplication of DerivativesActual

The area of the square increases at the rate of 0.5 ~cm ² / sec . The rate at which its perimeter is increasing when the side of the square is 10 ~cm long, is

Options

  1. A0 3 ~cm / sec
  2. B0 1 ~cm / sec
  3. C0 2 ~cm / sec
  4. D0 4 ~cm / sec

Correct answer

B. 0 1 ~cm / sec

Step-by-step solution

(D) Let x be the side of the square. Then area A=x² d A dt =2 x dx dt 0.5=2(10) d x dt dx dt =0.025 Now perimeter =4 x = p dp dt =4 dx dt =4(0.025)=0.1 ~cm / sec .

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