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MHT CET202019 Oct 2020Evening ShiftMathematicsApplication of DerivativesActual

The equation of the normal to the curve 2 x²+y²=12 at the point (2,2) is

Options

  1. A2 x-y+6=0
  2. B2 x+y-6=0
  3. Cx+2 y+2=0
  4. Dx-2 y+2=0

Correct answer

D. x-2 y+2=0

Step-by-step solution

(A) Given equation of the curve is 2 x²+y²=12 4 x+2 y d y d x =0 d y d x = -2 x y Slope of tangent at (2,2) is -2(2) 2 -2 Slope of normal at (2,2) is 1 2 Equation of normal at (2,2) is y-2= 1 2 (x-2) 2 y-4=x-2 x-2 y+2=0

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