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MHT CET20192 May 2019Morning ShiftMathematicsApplication of DerivativesActual

The equation of normal to the curve y = l o g e x at the point P 1 , 0 is ________

Options

  1. A2 x + y = 2
  2. Bx - 2 y = 1
  3. Cx - y = 1
  4. Dx + y = 1

Correct answer

D. x + y = 1

Step-by-step solution

Given curve is y = log e ⁡ x and point p 1 , 0 then, d y d x = 1 x Hence, equation of normal is y = - 1 x - 1 ⇒ x + y = - 1 ¯

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