Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202619 April 2026Morning ShiftMathematicsArea Under CurvesActual

The area (in sq. units) of the region enclosed by (x, y) y x^2, xy 8, y 1 is...

Options

  1. A8 2 - 14 3
  2. B8 2 + 7 3
  3. C16 2 + 7 3
  4. D16 2 - 14 3

Correct answer

D. 16 2 - 14 3

Step-by-step solution

The region is bounded by the curves y = x^2 , xy = 8 , and y = 1 in the first quadrant (as the area must be finite). To find the intersection points of the curves: Intersection of y = x^2 and xy = 8 : x(x^2) = 8 x^3 = 8 x = 2 At x = 2 , y = 4 . Intersection of y = x^2 and y = 1 : x^2 = 1 x = 1 (taking x > 0 ). Intersection of xy = 8 and y = 1 : x(1) = 8 x = 8 . The area can be calculated by integrating with respect to y from y = 1 to y = 4 . For a given y , the value of x ranges from the parabola x = y to the hyper

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Find the area bounded by the curve y = |2 - x| , the x –axis, and the lines x = 0 and x = 5 2026The area enclosed by the curve y = -x^2 and the line x + y + 2 = 0 is 2026The area of the region bounded by the line y = x + 2 and the curve x = -y^2 is 2026The area of the region in the first quadrant enclosed by the x -axis, the line x = 3 ,y and the circle x^2 + y^2 = 4 is 2026The area of the region bounded by the curve y^2 = x^3 , the y -axis and the lines y = 1 and y = 8 is 2026The area enclosed by the curve x = 3 , y = 3 is 2026The area in square units of the region bounded by the curve y = 16 - x^2 and lines x = 0, x = 4 above the X-axis is 2026The area bounded by the curves y = |x| - 1 and y = -|x| + 1 is 2026 Full Area Under Curves list All MHT CET PYQs