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MHT CET202411 May 2024Morning ShiftMathematicsArea Under CurvesActual

The area of the region lying in the first quadrant by y=4 x^2, x=0, y=2, y=4 is

Options

  1. A1 6 [8-2 2 ] sq.units
  2. B1 3 [8-2 2 ] sq.units
  3. C[8-2 2 ] sq.units
  4. D[8+2 2 ] sq.units

Correct answer

B. 1 3 [8-2 2 ] sq.units

Step-by-step solution

aligned Required area & = ₂^4 y 2 ~d y & = 1 2 [y^ 3 2 ]₂^4 3 2 & = 1 3 (8-2 2 ) sq. units aligned

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