For L. P. P, maximize z = 4 x 1 + 2 x 2 subject to 3 x 1 + 2 x 2 ≥ 9 , x 1 - x 2 ≤ 3 , x 1 ≥ 0 , x 2 ≥ 0 has ….

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Correct answer: B. Unbounded solution

We have, maximise z = 4 x 1 + 2 x 2 Subject to constracts, 3 x 1 + 2 x 2 ≥ 9 , x 1 - x 2 ≤ 3 , x 1 ≥ 0 , x 2 ≥ 0 On taking given constraints as equation, we get the following graphs Here, we get feasible region is unbounded.

For L. P. P, maximize z = 4 x 1 + 2 x 2 subject to 3 x 1 + 2 x 2 ≥ 9 , x 1 - x 2 ≤ 3 , x 1 ≥ 0 , x 2 ≥ 0 has ….

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