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AP EAMCET202422 May 2024Morning ShiftMathematicsApplication of DerivativesActual

Displacement s of a particle at time t is expressed as s=2 t^3-9 t . Find the acceleration at the time when the velocity vanishes.

Options

  1. A6
  2. B6 3
  3. C6 6
  4. D3 6

Correct answer

C. 6 6

Step-by-step solution

s=2 t^3-9 t Velocity = d s d t =6 t^2-9=0 t= 3 6 Acceleration = d^2 s d t^2 = .12 t d^2 s d t^2 |_ (t= 3 6 ) =6 6

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