Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. If PS and RQ intersect at a point X on the circumference of the circle, then 2 r equals

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Correct answer: A. PQ RS

Consider the given figure, In PXR , X =90^ PRX =90^ - ...(i) In PRS, array ll & = RS PR = RS 2 r ...(ii) & In PRQ , PRQ =90^ - & (90^ - )= PQ PR = PQ 2 r & = PQ 2 r & = 2 r PQ ...(iii) array from (ii) and (iii), we get aligned & RS 2 r = 2 r PQ & 2 r = PQ RS aligned

Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. If PS and RQ intersect at a point X on the circumference of the circle, then 2 r equals

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