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MHT CET20249 May 2024Morning ShiftMathematicsCircleActual

The equation of the circle, the end points of whose diameter are the centres of the circles x^2+y^2+6 x-14 y+5=0 and x^2+y^2-4 x+10 y-4=0 is x^2+y^2-4 x+10 y-4=0 is

Options

  1. Ax^2+y^2-x-2 y+41=0
  2. Bx^2+y^2+x-2 y-41=0
  3. Cx^2+y^2+x-2 y-41=0
  4. Dx^2+y^2-x+2 y-41=0

Correct answer

C. x^2+y^2+x-2 y-41=0

Step-by-step solution

Center of circle x^2+y^2+6 x-14 y+5=0 is (-3,7) and centre of circle x^2+y^2-4 x+10 y-4=0 is (2,-5) Equation of the required circle is aligned & (x+3)(x-2)+(y-7)(y+5)=0 & x^2+y^2+x-2 y-41=0 aligned

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