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MHT CET20243 May 2024Evening ShiftMathematicsCircleActual

The tangent to the circle x^2+y^2=5 at (1,-2) also touches the circle x^2+y^2-8 x+6 y+20=0 then the co-ordinates of the corresponding point of contact is

Options

  1. A(3,-1)
  2. B(3,1)
  3. C(-3,-1)
  4. D(-3,1)

Correct answer

A. (3,-1)

Step-by-step solution

Equation of the tangent at (1,-2) to the circle x^2+y^2=5 is x-2 y=5 Here, only point (3,-1) lies on the tangent.

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